1029=16t^2

Solution for 1029=16t^2 equation:

1029=16t^2

We move all terms to the left:

1029-(16t^2)=0

a = -16; b = 0; c = +1029;
Δ = b2-4ac
Δ = 02-4·(-16)·1029
Δ = 65856
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{65856}=\sqrt{3136*21}=\sqrt{3136}*\sqrt{21}=56\sqrt{21}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-56\sqrt{21}}{2*-16}=\frac{0-56\sqrt{21}}{-32}
=-\frac{56\sqrt{21}}{-32}
=-\frac{7\sqrt{21}}{-4}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+56\sqrt{21}}{2*-16}=\frac{0+56\sqrt{21}}{-32}
=\frac{56\sqrt{21}}{-32}
=\frac{7\sqrt{21}}{-4}
$